Letbe a Salem number of degree 6 with minimal polynomial
given by (2.1). Then
if and only if
, where A,B and C are positive integers satisfying
,
,
with the further condition that if A + B - 1 = C, then A = C and B = 1.
Suppose the beta expansion ofis
, so that the characteristic polynomial is
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Let
be the minimal polynomial of
. If this is to divide
, then the quotient must be of the form x + d for some integer
. By a result of Parry mentioned earlier, since -d is a root of
other than
, it must satisfy |d| < 2 and hence
. From (4.4),
, and since
by Parry's criterion, we must have d = 1. Equating the coefficients of
with those of (4.4) thus shows that
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The conditions
for all n imply
,
and
. The conditions
and
imply
and
. Finally, if
, i.e., C = A + B - 1, then we must have
, that is
; but
implies
, so in this case A = C and hence B = 1.
To finish the proof, we must verify that Parry's criterion follows from the inequalities in the statement of the proposition, the equation (4.5) defining
for
, and the assumed periodicity of
. This involves checking only a finite number of cases: for example, to verify that
, we note that
follows from
, and that if
, then A = C and B = 1, so
(always true here), and
. The remaining cases are similar and left to the reader.
Finally, we must verify that the exact period is 6 and not a divisor of 6. For example, if p=1, then (4.5) would imply that A=C and B=2. Then we find that
, so that
and hence P is reducible. Similarly, p=2 or p=3 lead to
and the reducibility of P.