There is a positive constantsuch that
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where
is the constant defined in Theorem D.
Suppose. Then
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where
and
and
. Now Theorem D shows that
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and Theorem E shows that
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where
and
is a constant by Theorem C. Now
![]()
using the binomial theorem and Stirling's formula. Hence
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Then this inequality and (2.22) imply (2.21) with
.