where the limit is taken p--adically.
Proof: Suppose that
. If
then
divides the numerator of both
and
. If
and r is sufficiently large then
so that
Therefore, letting
and then
, we obtain (10.1).
where the limit here is taken p-adically: Note that this limit
exists and is well defined by (8.2); moreover
for all odd n.
(Using Theorem 5.11 of [21], one can also show that
,
where
is the p--adic L--function, and
is that
p--adic
st root of unity for which
.)
Our main result of this section is
Proposition 4. For any integer x we have
where
(
) is chosen so that
, and
Remark: Note that
if
, and
if p=2.
(Using Theorem 5.11 of [21], one can also show that
where
: note that
has a pole at s=1.)
Proof: As
whenever
p does not divide j, we have
by Proposition 3. Now, fix
and take
with r
large in (8.3), so
that
for all sufficiently large r, as
for those k in the sum.
Therefore, letting
and then
, we obtain (10.2).