Proof: Suppose that . If then divides the numerator of both and . If and r is sufficiently large then
so that Therefore, letting and then , we obtain (10.1). where the limit here is taken p-adically: Note that this limit exists and is well defined by (8.2); moreover for all odd n. (Using Theorem 5.11 of [21], one can also show that , where is the p--adic L--function, and is that p--adic st root of unity for which .)Our main result of this section is
Proposition 4. For any integer x we have where () is chosen so that , and
Remark: Note that if , and if p=2.
(Using Theorem 5.11 of [21], one can also show that
where : note that has a pole at s=1.)Proof: As whenever p does not divide j, we have
by Proposition 3. Now, fix and take with r large in (8.3), so that for all sufficiently large r, as for those k in the sum. Therefore, letting and then , we obtain (10.2).