Before specializing to the cubic case, we consider the general case of
binary forms of degree n. Let K be a field (usually ,
or
).
The roots of F in K are the solutions
of
. If
for
and
, the point at infinity
is a root of order exactly n-m
(if m=n, i.e
, it is of course not a root), and the other roots
are the roots in K of the polynomial
of degree m. In particular
if K is algebraically closed, F has always exactly n roots, counted with
multiplicity. Note that the point at infinity is rational over any base field,
algebraically closed or not.
Denote by , with
, the roots
of F in
. It is easily seen that we can choose representatives in
so that we have
If is a polynomial of degree exactly equal to n ( i.e if
), then one immediately checks that
.
In degrees up to 3 we have the following formulas.
If F is a form of degree n and is
a
matrix with coefficients in K we define the action of
on F by
.
Let. Then
We now restrict to the case of integral binary forms, i.e binary
forms whose coefficients are all in . As a corollary of the proposition,
we see that the action of
preserves the discriminant of F,
since
is even.
We will say that the form F is irreducible if is
irreducible as a polynomial in
. Equivalently, F is irreducible if
and the polynomial
is irreducible in
(or
).
We will say that an integral form F is primitive if the GCD of all its coefficients is equal to 1.
Let F be an integral form and. Then
is irreducible if and only if F is, and
is primitive if and only F is.