,
or
).
A binary form of degree n with coefficients in K is a homogeneous polynomial in two variables of degree n with coefficients in K, i.e an expression of the form

with
. We will write
as an abbreviation for
the above notation. In particular
is the binary quadratic form
, and
is the cubic form
.
The roots of F in K are the solutions
of
. If
for
and
, the point at infinity
is a root of order exactly n-m
(if m=n, i.e
, it is of course not a root), and the other roots
are the roots in K of the polynomial
of degree m. In particular
if K is algebraically closed, F has always exactly n roots, counted with
multiplicity. Note that the point at infinity is rational over any base field,
algebraically closed or not.
Denote by
, with
, the roots
of F in
. It is easily seen that we can choose representatives in
so that we have

Of course the choice of representative is not unique: for each i we can
change
into
as long
as
. We will always assume that the
representatives of the roots are chosen in this manner.
We define the discriminant of the form F by the following formula:

This makes sense since if we change
into
with
,
the product is multiplied by

If
is a polynomial of degree exactly equal to n ( i.e if
), then one immediately checks that
.
In degrees up to 3 we have the following formulas.



If F is a form of degree n and
is
a
matrix with coefficients in K we define the action of
on F by
.
Let. Then
We now restrict to the case of integral binary forms, i.e binary
forms whose coefficients are all in
. As a corollary of the proposition,
we see that the action of
preserves the discriminant of F,
since
is even.
We will say that the form F is irreducible if
is
irreducible as a polynomial in
. Equivalently, F is irreducible if
and the polynomial
is irreducible in
(or
).
We will say that an integral form F is primitive if the GCD of all its coefficients is equal to 1.
Let F be an integral form and. Then
is irreducible if and only if F is, and
is primitive if and only F is.