Multiplication is a different story. Usual multiplication of two n-digit integers has bit complexity and no better. However, it is possible to multiply two n-digit integers with complexity . This result is due to Schönhage and Strassen and dates from 1971 . It provides the best bound known for multiplication. No multiplication can have speed better than . Unhappily, more exact results aren't available.
The original observation that a faster than multiplication is possible was due to Karatsuba in 1962. Observe thatand thus multiplication of two 2n-digit integers can be reduced to three multiplications of n-digit integers and a few extra additions. (Of course multiplication by is just a shift of the decimal point.) If one now proceeds recursively one produces a multiplication with bit complexity Note that . We denote by the bit complexity of multiplying two n-digit integers together by any method that is at least as fast as usual multiplication.
The trick to implementing high precision arithmetic is to get the multiplication right. Division and root extraction piggyback off multiplication using Newton's method. One may use the iterationto compute and the iteration to compute . One may also compute from and so avoid divisions in the computation of . Not only do these iterations converge quadratically but, because Newton's method is self-correcting (a slight perturbation in does not change the limit), it is possible at the kth stage to work only to precision . If division and root extraction are so implemented, they both have bit complexity , in the sense that n-digit input produces n-digit accuracy in a time bounded by a constant times the speed of multiplication. This extends in the obvious way to the solution of any algebraic equation, with the startling conclusion that every algebraic number can be computed (to n-digit accuracy) with bit complexity . Writing down n digits of or is (up to a constant) no more complicated than multiplication. The Schönhage-Strassen multiplication is hard to implement. However, a multiplication with complexity based on an ordinary complex (floating point) fast Fourier transform is reasonably straightforward. This is Kanada's approach, and the recent records all rely critically on some variations of this technique.
To see how the fast Fourier transform may be used to accelerate multiplication, let and be the representations of two high-precision numbers in some radix b. The radix b is usually selected to be some power of 2 or 10 whose square is less than the largest integer exactly representable as an ordinary floating-point number on the computer being used. Then, except for releasing each ``carry'', the product of x and y may be written as
Now consider x and y to have n zeros appended, so that x, y, and z all have length N =2n. Then a key observation may be made: the product sequence z is precisely the discrete convolution : where the subscript k-j is to be interpreted as k-j +N if k-j is negative.
Now a well-known result of Fourier analysis may be applied. Let denote the discrete Fourier transform of the sequence x, and let denote the inverse discrete Fourier transform of x:Then the ``convolution theorem'', whose proof is a straightforward exercise, states that or, expressed another way, Thus the entire multiplication pyramid z can be obtained by performing two forward discrete Fourier transforms, one vector complex multiplication and one inverse transform, each of length N =2n. Once the real parts of the resulting complex numbers have been rounded to the nearest integer, the final mutiprecision product may be obtained by merely releasing the carries modulo b. This may be done by starting at the end of the z vector and working backward, as in elementary school arithmetic, or by applying other schemes suitable for vector processing on more sophisticated computers.
A straightforward implementation of the above procedure would not result in any computational savings --- in fact, it would be several times more costly than the usual ``schoolperson'' scheme. The reason this scheme is used is that the discrete Fourier transform may be computed much more rapidly using some variation of the well-known ``fast Fourier transform'' (FFT) algorithm . In particular, if , then the discrete Fourier transform may be evaluated in only arithmetic operations using an FFT. Direct application of the definition of the discrete Fourier transform would require floating-point arithmetic operations, even if it is assumed that all powers of have been precalculated.
This is the basic scheme for high-speed multiprecision multiplication. Many details of efficient implementations have been omitted. For example, it is possible to take advantage of the fact that the input sequences x and y and the output sequence z are all purely real numbers, and thereby sharply reduce the operation count. Also, it is possible to dispense with complex numbers altogether in favor of performing computations in fields of integers modulo large prime numbers. Interested readers are referred to , , , and . When the costs of all the constituent operations, using the best known techniques, are totalled both Algorithms 1 and 2 compute n digits of with bit complexity , and use full precision operations.
The bit complexity for Sum 1, or for using any of the arctan expansions, is between and depending on implementation. In each case, one is required to sum terms of the appropriate series. Done naively, one obtains the latter bound. If the calculation is carefully orchestrated so that the terms are grouped to grow evenly in size (as rational numbers) then one can achieve the former bound, but with no corresponding reduction in the number of operations. The Archimedean iteration of section 2 converges like so in excess of n iterations are needed for n-digit accuracy, and the bit complexity is .
Almost any familiar transcendental number such as e, , , or Catalan's constant (presuming the last three to be nonalgebraic) can be computed with bit complexity or . None of these numbers is known to be computable essentially any faster than this. In light of the previous observation that algebraic numbers are all computable with bit complexity , a proof that cannot be computed with this speed would imply the transcendence of . It would, in fact, imply more, as there are transcendental numbers which have complexity . An example is . It is also reasonable to speculate that computing the nth digit of is not very much easier than computing all the first n digits. We think it very probable that computing the nth digit of cannot be .